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A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. Then the elastic energy stored in the wire is : |
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Answer» 0.2 J `=1/2` Force `xx` EXTENSION `=1/2xx200xx1xx10^(-3)=0.1J` Thus correct choice is (d). |
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