1.

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. Then the elastic energy stored in the wire is :

Answer»

0.2 J
10 J
20 J
0.1 J

Solution :WORK done =`1/2`Stress `XX` Strain `xx` Volume
`=1/2` Force `xx` EXTENSION
`=1/2xx200xx1xx10^(-3)=0.1J`
Thus correct choice is (d).


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