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A wire suspended vertically from one of itsends is strached by attached a weight of `200 N` to the lower end . The weight streches the wire by `1 mm` . Then the elastic energy stored in the wire isA. `0.1J`B. `0.2J`C. `10J`D. `20` |
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Answer» Correct Answer - A `U=(1)/(2)xxFxxl=(1)/(2)xx200xx10^-3=0.1J` |
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