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A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's age is

Answer» Let x and y be the ten's and unit's digits respectively of the numeral denoting the woman's age. Then, woman's age = (10X + y) years; husband's age = (10y + x) years. Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y) (9y-9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)y Clearly, y should be a single-digit multiple of 5, which is 5. So, x = 4, y = 5. Hence, woman's age = 10x + y = 45 years.


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