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A word consist of 9 letters; 5 consonants and 4 vowels. Three lettersare chosen at random. What is the probability that more than one vowel willbe selected?

Answer» 9 letters=5 constant,4vowels
`.^9C_3`-total ways
Favorable cases->Vowels->more than one
2 vowels=`.^4C_2*.^5C_1`
3 vowels=`.^4C_3*.^5C_0`
`P=(.^4C_2*.^5C_1+.^4C_3*.^5C_0)/(.^9C_3)`.


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