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A worker reaches his workplace 15 minutes late when he walks at a speed of 4km/hr from his house . The next day he increases his speed by 2 km/hr and reaches his work place on time . Find the distance from his house to his workplace ? |
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Answer» - → The MAN reaches 15 mins late at SPEED of 4 km/hr → Next day increases his speed by 2 km/hr and reaches on time To Find :- → Distance b/w his house and the workplaceSolution :- → Let that distance be X ★ Day 1 ★→ Speed = 4 km/hr → Distance covered = x km→ Time taken will be ★ Day 2 ★→ Speed = 4 km/hr + 2 km/hr = 6 km/hr → Distance Covered = x km→ Time taken will be → As he was 15 mins late , let's COVERT it into hours → If we will add 1/4 hrs to time taken on day 2 we will get the time taken on Day 1 . So, the equation will be → Let's solve this equation ! ∴ The distance b/w his house and the workplace is 3 km |
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