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(A) Write the chemical equation for the reaction involved in Cannizzaro reaction. (b) Draw the structure of the semicarbazone of ethanal. (c ) Why pK_(a)of F- CH_(2) - COOH is lower than that of Cl - CH_(2) -COOH ? (d) Write the product in the following reaction : CH_(3) -CH= CH- CH_(2) CN underset((ii) H_(2)O)overset((i)DIBAL-H)(rarr)(e ) How can you distinguish between propanal and propanone ? |
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Answer» Solution :(a) Cannizzaro.s reaction `HCHO+HCHO UNDERSET(NaOH)overset("Conc.")(rarr)underset("Sodium formate")(HCOONa)+underset("Methyl alcohol")(CH_(3)OH)` (b) `underset("Semi carbazone of ethanal")(CH_(3)CH = N N HCONH_(2))` (c ) Fluorine has a stronger -I inductive effect than chlorine. Therefore, fluoroacetic acid is stronger than chloroacetic acid. Greater the acid strength, smaller is the `pK_(a)` value `pK_(a)= - log K_(a)` Therefore, `F - CH_(2) COOH` hasa lower `pK_(a)` value than `CL - CH_(2) COOH` (d ) `CH_(3) - CH = CH - CH_(2) CN underset((ii) H_(2)O)overset( (i)DIBAL-H)(rarr) CH_(3) - CH = CH - CH_(2) CHO` ( e ) Propanal GIVES the Tollen.s reagent test while propanone does not. Silver mirror is formed on adding ammonical silver nitrate solution to propanal and heating. |
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