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A Young's double-slit interference arrangement with slits S_1 and S_2 is immersed in water (refractive index = 4/3) as shown in the figure. The positions of maxima on the surface of water are given by x^2 = p^2m^2lambda^2 - d^2, where lambda is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an interger. The value of p is {:(0,1,2,3,4,5,6,7,8,9):} |
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Answer» `mu sqrt(d^2 + x^2) - sqrt(d^2 + x^2) = m lambda` `IMPLIES (mu - 1) sqrt(d^2 + x^2) = m lambda` `implies (4/3 - 1) sqrt(d^2 + x^2) = m lambda` `implies d^2 + x^2 = 9 m^2 lambda^2` On comparing with the given result we GET p = 3. |
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