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A zeo order reaction X rarrProduct, with an initial concentration 0.02 M has a half life of 10 min . If one starts with concentration 0.04 M , then the half life is .... |
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Answer» 10 s for n = 0 `t_(1//2)=1/(2k[A_0]^(-1))` `t_(1//2)=([A_0])/(2k)` `t_(1//2)=prop[A_0]""....(1) ` Given `[A_0]=0.02M , t_(1//2)=10 min ` `[A_0]=0.04 M , t_(1//2)`= ? Substitute in (1) ` 10 min prop 0.02 M ""...(2)` `t_(1//2) prop 0.4 M ""...(3)` Dividing Eq. (3) by Eq . (2) we get , `implies (t^(1//2))/(10 min )=(0.04M)/(0.02M)` `t_(1//2)=2xx10 ` min = 20 min . |
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