A zinc rod is placed in 0.095 M zinc chloride solution at 25^(@)C. emf – InterviewSolution

1.	A zinc rod is placed in 0.095 M zinc chloride solution at 25^(@)C. emf of this half cell is -0.79V. Calculate E_(Zn^(2+)//Zn)^(@).
Answer» SOLUTION :`-0.76V`

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