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A²+2a+2, 3a²+6a+6, 4a²+5a+4 are in A.P, find out the value of a |
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Answer» Answer: 3a^2+6a+6-(a^2+2a+2) =4a^2+5a+4-(3a^2+6a+6) 3a^2+6a+6-a^2-2a-2=4a^2+5a+4-3a^2-6a-6 2a^2+4a+4=a^2-a-2 a^2+5a+6=0 a^2+3a+2a+6=0 a(a+3) +2(a+3) =0 (a+2) (a+3) =0 a+2=0 a=-2 a+3=0 a=-3 a=-2 and a=-3 |
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