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A²+8a+15 factorise by using suitable identity |
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Answer» Answer: Step by Step Solution More Icon STEP : Trying to factor by splitting the middle term The first term is, a2 its coefficient is 1 . The middle term is, +8a its coefficient is 8 . The last term, "the constant", is +15 Step-1 : Multiply the coefficient of the first term by the constant 1 • 15 = 15 Step-2 : Find two factors of 15 whose sum equals the coefficient of the middle term, which is 8 . -15 + -1 = -16 -5 + -3 = -8 -3 + -5 = -8 -1 + -15 = -16 1 + 15 = 16 3 + 5 = 8 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 5 a2 + 3a + 5a + 15 Step-4 : Add up the first 2 terms, pulling out like factors : a • (a+3) Add up the last 2 terms, pulling out common factors : 5 • (a+3) Step-5 : Add up the four terms of step 4 : (a+5) • (a+3) Which is the DESIRED factorization Final result : (a + 5) • (a + 3) Step-by-step explanation: |
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