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A5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass = "60 g mol"^(-1)) in the same solvent. If the densities of both the solutions are assumed to be equal to "1.0 g cm"^(-3), molar mass of the substance will be |
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Answer» `"210.0 g MOL"^(-1)` Molar conc. Of the SUBSTANCE = Molar conc. Of urea `(52.5gL^(-1))/(M)=(15gL^(-1))/("60 g mol"^(-1))` `("100 g solution = 100 mL as d = 1 g mL"^(-1))` `therefore""M=(52.5xx60)/(15)="210 g mol"^(-1)` |
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