AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre of the circle, then find the angle subtended by chord CD at the centre of the circle.please answer or please send me the figure of this question.IF YOU WILL ANSWER ME THIS QUESTION I WILL MARK YOU BRAINLIST. Plz plz plz its urgent

AB and CD are two chords such that AB = CD. If chord AB subtend an a

1.	AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre of the circle, then find the angle subtended by chord CD at the centre of the circle.please answer or please send me the figure of this question.IF YOU WILL ANSWER ME THIS QUESTION I WILL MARK YOU BRAINLIST. Plz plz plz its urgent
Answer» Given- AB and CD are two chords of a CIRCLE with CENTRE O. OM⊥AB and ON⊥CD AM=AN=4.5 cm OM=ON=2 cm Solution- AM=AN=4.5 cm ∴AB=AM+AN=(4.5+4.5) cm =9 cm OM and ON are the perpendicular distances of AB and CD respectively. Since OM⊥AB and ON⊥CD Now OM=ON=2 cm ∴AB and CD are equidistant from O. ∴AB=CD Since chords of a circle, which are equidistant from the centre of the same circle are EQUAL in length. ∴AB=CD=9 cmhope it helps U ✌✌✌✌