AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre of the circle, then find the angle subtended by chord CD at the centre of the circle.

AB and CD are two chords such that AB = CD. If chord AB subtend an a

1.	AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre of the circle, then find the angle subtended by chord CD at the centre of the circle.
Answer» pls MARK me brainliestStep-by-step explanation:Given- AB and CD are two CHORDS of a CIRCLE with centre O. OM⊥AB and ON⊥CD AM=AN=4.5 cm OM=ON=2 cm SOLUTION- AM=AN=4.5 cm ∴AB=AM+AN=(4.5+4.5) cm =9 cm OM and ON are the perpendicular distances of AB and CD respectively. Since OM⊥AB and ON⊥CD Now OM=ON=2 cm ∴AB and CD are equidistant from O. ∴AB=CD Since chords of a circle, which are equidistant from the centre of the same circle are equal in length. ∴AB=CD=9 cm