AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre ofthe circle, then find the angle subtended by chordCD at the centre of the circle.

AB and CD are two chords such that AB = CD. If chord AB subtend an a

1.	AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre ofthe circle, then find the angle subtended by chordCD at the centre of the circle.
Answer» -step explanation:What would you like to ask?9thMathsCirclesPerpendicular to a Chord through the CentreO is the centre of the circ...MATHSO is the centre of the circle. AB and CD are two CHORDS of the circle. OM⊥AB and ON⊥CD. If OM=ON=2 CM and AM=BM=4.5 cm, then CD is EQUAL toMEDIUMShareStudy laterANSWERGiven- AB and CD are two chords of a circle with centre O.OM⊥AB and ON⊥CDAM=AN=4.5 cmOM=ON=2 cm Solution-AM=AN=4.5 cm∴AB=AM+AN=(4.5+4.5) cm =9 cmOM and ON are the PERPENDICULAR distances of AB and CD respectively.Since OM⊥AB and ON⊥CD Now OM=ON=2 cm∴AB and CD are equidistant from O.∴AB=CDSince chords of a circle, which are equidistant from the centre of the same circle are equal in length.∴AB=CD=9 cmplease MARK me as a BRAINLIST

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AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre ofthe circle, then find the angle subtended by chordCD at the centre of the circle.​

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AB and CD are two chords such that AB = CD. If chord AB subtend an angle of 45° at the centre ofthe circle, then find the angle subtended by chordCD at the centre of the circle.