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(AB + CB) × 4 = 520, where A, B and C are positive integers, then Value of B can be |
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Answer» Answer: Answer a b
= b c
=(INTEGER) b =ac⇒c= a b 2
3 a+b+c
=b+2 a+b+c=3b+6⇒a−2b+c=6 a−2b+ a b 2
=6⇒1− a 2b
+ a 2
b 2
= a 6
( a b
−1) 2 = a 6
⇒a=6 only |
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