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    				| 1. | `AB` is a potentiometer wire of length `100 cm`. When a cell `E_(2)` is connected across `AC`, where `AC = 75 cm`, no current flows from `E_(2)`. The internal resistance of the cell `E_(1)` is negligible. Find emf of the cell `E_(2)`.A. `2 V`B. `1.5 V`C. `1 V`D. `1.75 V` | 
| Answer» Correct Answer - B `k = (E_(1))/(100) = (2)/(100) 0.02 V cm^(-1)` `E_(2) = k(75) = 0.02 xx 75 = 1.5 V` | |