1.

In the above question, the reading of ammeter is `200//x mA`. What is the value of `x`?

Answer» Correct Answer - `(3)`
`(4 - V_(1))/(100) = (V_(1) - 1)/(100) + (V_(1) - 0)/(100)` or `V_(1) = (5)/(3) V`
Current in ammeter (II)`= (V_(1) - 1)/(R ) = ((5//3) - 1)/(200) = (2)/(300) A = (20)/(3) mA`


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