Saved Bookmarks
| 1. |
ABC is a right angle triangle at b if d and e are midpoints of sides BC CA and ab respectively prove that a b square + c square is equals to 5 de square |
|
Answer» Given: A right triangle ABC, right angled at C. D and E are points on sides AC and BCrespectively.To Prove : AE2 + BD2 = AB2 + DE? = Const: Join AE, BD and DE.Proof: In AACE AE? = AC2 + CE2 ..(1)[Using Pythagoras theorem] In ABCD, BD2 = CD2 + BC2 ..(ii)[Using Pythagoras theorem]Adding (i) and (ii), we get AE? + BD? = (AC2 + BC?) + (CE? + CD²) AE? + BD2 = AB² + DE? HENCE Proved.Step-by-step EXPLANATION: |
|