ABC is a right angle triangle c and m is midpoint of AB and MD paralle

1.	ABC is a right angle triangle c and m is midpoint of AB and MD parallel BC prove that cm=ma=1/2ab
Answer» ANSWER: In ∆ABC, we have M is the midpoint of AB and MD\|\|BC D is the midpoint of AC {by converse of midpoint THEOREM} Now MP\|\|BC Thus;MD PERPENDICULAR AC Join MC In ∆MDA and ∆MDC we have DA=DC MD=MD ∆MDA~∆MDC {S.A.S} And so MA=MC Now M is the midpoint of AB MA=MC=1/2AB Step-by-step explanation: sorry no FIGURE

ABC is a right angle triangle c and m is midpoint of AB and MD parallel BC prove that cm=ma=1/2ab

Answer»

In ∆ABC, we have

M is the midpoint of AB and MD||BC

D is the midpoint of AC {by converse of midpoint THEOREM}

Now

MP||BC

Join MC

In ∆MDA and ∆MDC we have

DA=DC

MD=MD

∆MDA~∆MDC {S.A.S}

And so MA=MC

Now M is the midpoint of AB

MA=MC=1/2AB

Step-by-step explanation: sorry no FIGURE