ABC is a right triangle right-angled at C.let BC = a , CA = b , AB = c and let p be the length of perpendicular from C on AB , prove that (1) cp=ab(2) 1/p2 = 1/a2 + 1/b2

ABC is a right triangle right-angled at C.let BC = a , CA = b , AB = c

1.	ABC is a right triangle right-angled at C.let BC = a , CA = b , AB = c and let p be the length of perpendicular from C on AB , prove that (1) cp=ab(2) 1/p2 = 1/a2 + 1/b2
Answer» 1. ↦ Area is 1/2 base * height . So for the same TRIANGLE area can be 1/2ba and can be 1/2pC. Hence cp = ab2. ↦ From above P2 = a2b2/c21/p2 = c2/ a2b2but for right triangle c2 = a2 +b2Hence 1/p2 = (a2+b2)/ a2b2Hence 1/p2 = 1/a2+1/b2

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ABC is a right triangle right-angled at C.let BC = a , CA = b , AB = c and let p be the length of perpendicular from C on AB , prove that (1) cp=ab(2) 1/p2 = 1/a2 + 1/b2​

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ABC is a right triangle right-angled at C.let BC = a , CA = b , AB = c and let p be the length of perpendicular from C on AB , prove that (1) cp=ab(2) 1/p2 = 1/a2 + 1/b2