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ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure). Show that i) ΔABD ≅ ΔACE ii) AB = AC i.e., ABC is an isosceles triangle. |
Answer» Given that BD ⊥ AC; CE ⊥ AC BD = CE Now in ΔABD and ΔACE ∠ADB = ∠AEC (∵ given 90°) ∠A = ∠A (commori angle) BD = CE ∴ ΔABD = ΔACE (∵ AAS congruence) ⇒ AB = AC (∵ C.P.C.T) |
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