1.

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure). Show that i) ΔABD ≅ ΔACE ii) AB = AC i.e., ABC is an isosceles triangle.

Answer»

Given that BD ⊥ AC; CE ⊥ AC 

BD = CE 

Now in ΔABD and ΔACE 

∠ADB = ∠AEC (∵ given 90°) 

∠A = ∠A (commori angle)

BD = CE 

∴ ΔABD = ΔACE (∵ AAS congruence)

⇒ AB = AC (∵ C.P.C.T)



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