1.

ABC is an equilateral triangle. Charged of +q are placed at each corner. The electric field at O will be(##U_LIK_SP_PHY_XII_C01_E04_006_Q01.png" width="80%">

Answer»

` (1)/( 4pi in _0) .(q)/(r^(2))`
` (1)/(4pi in _0).(q)/® `
`0`
` (1)/(4pi in _0) .(3q)/(r^(2))`

Solution :NET field at O is zero because `E_A=E_B=E_C ` and the three fields are mutually inclined at ` 120^(@) ` each and their resultant is zero.


Discussion

No Comment Found

Related InterviewSolutions