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ABC is an isosceles triangle in which `A B =A C`. AD bisects exterior angle PAC and `C D ||A B`. Show that(i) `/_D A C =/_B C A ` and (ii) ABCD is a parallelogram. |
Answer» ABC is a isosceles triangle `/_ABC=/_ACB` 1)`/_DAC=/_BCA` `/_PAC=/_ACB+/_ABC` `/_PAC=theta+theta=2theta` 2)ABCD is a parallelogram. AD||AC CD||AB. |
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