1.

ABC is any triangle and P is a point on the side BC. If Q is a point such that bar(PQ)=bar(AP)+bar(PB)+bar(PC), then

Answer»

`BAR(AQ)=bar(AB)+bar(BC)+bar(AC)`
Q is fixed for all position of P on BC
Q depends on the position of P
`bar(AQ)=bar(AB)+bar(AC)-bar(BC)`

ANSWER :B


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