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ABCD is a parallelogram. If ∠BAD = 110°, then ∠DCE =A) 70° B) 55° C) 35° D) 60° |
Answer» Correct option is (A) 70° \(\because\) \(\angle C\;\&\;\angle A\) are opposite angle in parallelogram ABCD. \(\therefore\) \(\angle C=\angle A\) = \(110^\circ\) \(\Rightarrow\) \(\angle BCD\) = \(110^\circ\) Since, \(\angle BCD\;\&\;\angle DCE\) form a linear pair. \(\therefore\) \(\angle BCD+\angle DCE\) = \(180^\circ\) \(\Rightarrow\) \(\angle DCE\) \(=180^\circ-\angle BCD\) \(=180^\circ-110^\circ\) = \(70^\circ\) Correct option is A) 70° |
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