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ABCD is a parallelogram in which AB = 20 cm, BC = 13 cm, AC = 21 cm. Find the area of parallelogram ABCD |
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Answer» ABCD is a //GM in which AB = 20cm and BC =13cmAC=21 CMAREA of //gmDiagramTaking Small ∆s∆ABDOnce Again∆ABCSolution∆ABDFrom Heron's Formula¶utting the value=>√3×3×3×7×2×3×2×7=>3×3×2×7=>126cm²Properties of //gmOpposite sides equalDiagonal bisect the //gm in two equal AREA ThereforeArea of ∆ABC =. Area of ∆ABDRequired area of //gm ABCD is=>Area of ∆ABC + Area of ∆ABD=Area of //gm=>126+126=>252cm² |
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