Abcd is a quadrilateral . prove that (ab+b+cd+da)>(ac+bd)

1.	Abcd is a quadrilateral . prove that (ab+b+cd+da)>(ac+bd)
Answer» Step-by-step explanation: ABCD is a quadrilateral and AC, and BD are the diagonals. Sum of the two sides of a triangle is GREATER than the THIRD side. So, considering the triangle ABC, BCD, CAD and BAD, we get AB + BC > AC CD + AD > AC AB + AD > BD BC + CD > BD Adding all the above equations, 2(AB + BC + CA + AD) > 2(AC + BD) ⇒ 2(AB + BC + CA + AD) > 2(AC + BD) ⇒ (AB + BC + CA + AD) > (AC + BD) ⇒ (AC + BD) < (AB + BC + CA + AD) thankyou PLZZ Mark's as brainlist

Answer»

Step-by-step explanation:

ABCD is a quadrilateral and AC, and BD are the diagonals.

Sum of the two sides of a triangle is GREATER than the THIRD side.

So, considering the triangle ABC, BCD, CAD and BAD, we get

AB + BC > AC

CD + AD > AC

AB + AD > BD

BC + CD > BD

Adding all the above equations,

2(AB + BC + CA + AD) > 2(AC + BD)

⇒ 2(AB + BC + CA + AD) > 2(AC + BD)

⇒ (AB + BC + CA + AD) > (AC + BD)

⇒ (AC + BD) < (AB + BC + CA + AD)

thankyou

PLZZ Mark's as brainlist

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