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ABCD is a quadrilateral such that AD = DC = CA = 20 units, BC = 12 units and ZABC = 90% What is the area of the quadrilateral ABCD? (Use √3= 1.73) |
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Answer» plzzzz follow meStep-by-step explanation:By applying heron's formula in triangle ABC having the sides 7 cm,6 cm and 9 cm, we HAVES= 27+6+9 =11 cmArea of triangle = s(s−a)(s−b)(s−c) = 11(11−7)(11−6)(11−9) = 440 cm 2 Now, in triangle ADC having sides 15 cm,12 cm and 9 cm, we haves= 215+12+9 =18 cm= 18(18−15)(18−12)(18−9) =54 cm 2 There, the area of quadrilateral ABCD=( 440 +54) cm 2 |
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