1.

ABCD is a rectangle and E F G and H are the mid-points of AB BC CD DA respectively Prove that EFGH is a rhombus

Answer» DE||BC
DE=`1/2`BC
HE||BD
HE=`1/2`BD
FG||BD
FG=`1/2`BD
We know, if 2 sides area parallel then its a parallelogram.
EFGH is a parallelogram
AC=BD
EF||AC
EF=`1/2`AC
EF=`1/2`BD.


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