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ABCD is a rectangle and E F G and H are the mid-points of AB BC CD DA respectively Prove that EFGH is a rhombus |
Answer» DE||BC DE=`1/2`BC HE||BD HE=`1/2`BD FG||BD FG=`1/2`BD We know, if 2 sides area parallel then its a parallelogram. EFGH is a parallelogram AC=BD EF||AC EF=`1/2`AC EF=`1/2`BD. |
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