1.

ABCD is a rectangle in which the diagonals intersect at P. Given that ∠APB = 100°, then the value of ∠ACB = a. 40° b. 50° c. 60° d. 40°

Answer»

ANSWER:

Step-by-step : angle APB+ angle BPC = 180°

100°+ angle bpc= 180°

Angle bpc =180°-100°

Angle bpc= 80°

Angle PCB = angle CBP

Angle bpc+ angle PCB+ angle CBP= 180°

80° + x + x = 180°

2x = 100°

X = 50°

Therefore, PCB = 50°


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