 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | ABCD is a rhombus in which `angleC= 60^(@)`then AC:BD=. A. `sqrt3 : 1`B. `sqrt3 : sqrt2`C. `3 : 1`D. `3 : 2` | 
| Answer» Correct Answer - A ABCD is a rhombus. So its all sides are equal. Now, `BC = DC rArr angleBDC = angleDBC =x^(@)` (say). Also, `angleBCD = 60^(@)` (given). `therefore x^(@)+x^(@)+60^(@)=180^(@)rArr2x=120rArrx = 60`. `therefore angle BDC=angleDBC=angleBCD=60^(@).` So, `triangleBCD` is an equilateral triangle. `therefore BD = BC =a`(say). `AB^(2)=OA^(2)+OB^(2)rArrOA^(2)=AB^(2)-OB^(2)=a^(2)-((a)/(2))^(2)=a^(2)-(a^(2))/4=(3a^(2))/(4)` `therefore AC : BD =sqrt3a : a=sqrt3 : 1`. | |