In figure, ABCD and AEFD are two parallelograms. Prove that `ar (Delta – InterviewSolution

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1.	In figure, ABCD and AEFD are two parallelograms. Prove that `ar (DeltaPEA) = ar (DeltaQFD)`.
Answer» `triangleCPD` and \|\|gm ABCD are on the same base DC and between the same prallels CD and AB. `therefore ar(triangleCPD)=(1)/(2)ar("\|\|gm ABCD").` Similarly, `ar(triangleAQD)=(1)/(2)ar("\|\|gm ABCD").` ` therefore ar(triangleCPD)=ar(triangleAQD).`

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