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XY is a line parallel to side BC of a triangle ABC. If `B E || A C`and `C F || A B`meet XY at E and F respectively, show that `a r (A B E) = a r (A C F)` |
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Answer» From diagram we can see that `ar(EBCY)=ar(BXFC)` `ar(/_AEB)=1/2ar(EBLY)` `arBXFC=2ar(/_AFC)` from both the equations ar(/_AEB)=ar(/_AFC) |
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