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ABCD is a square, BA=BQ, QRC and BPD are straight lines and ∠PBQ = 21°. Then, ∠BAQ equals(a) 60° (b) 84° (c) 78° (d) 74.5° |
Answer» (c) 78° Since the diagonal of a square bisects the angle at the vertices, ∠DBC = 45°. ∴ ∠ ABQ = 90° – (21° + 45°) = 90° – 66° = 24° In ΔBAQ, BA = BQ ⇒ ∠BQA = ∠BAQ (isos. Δ property) ∴ ∠BAQ = \(\frac{180°-24°}{2}=\frac{156°}{2}\) = 78°. |
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