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ABCD is a trapezium in which AB||CD, E and F are the mid points of AD and BCrespectively such that EF || AB. If AB = 12cm and EF = 10 cm then CD |
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Answer» -step explanation:ABCD is a trapezium in which AB∣∣DC and E,F are mid point of AD,BC respectivelyjoin CE and produce it to MEET BA produced at GIn △EDC and △EAGED=EA (e is mid point of AD=>∠CED=∠GEC (VERTICALLY OPPOSITE angles)=>∠ECD=∠EGA (alternating angles)SINCE,△EDC≅△EAG=>CD=GA and EC=EGin △CGBE is a mid point CG (EC=EG) provedF is a mid point of BC (given)since,by mid point THEOREM EF∣∣AB and EF=21 but GB=GA+AB=CD+AB Hence,EF∣∣AB and EF=21(AB+CD)Answered By |
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