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ABCD is a trapezium. P is the midpoint of BC. AB = 14 cm, DC = 6 cm. The distance between AB and CD is 8 cm. Find the area of the triangle AQD. |
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Answer»
ABCD is a trapezium. P is the midpoint of BC. AB = 14 cm, DC = 6 cm. The distance between AB and CD is 8 cm. Find the area of the triangle AQD. |
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