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ABCD is a trapezium such that AB || DC, |
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Answer» Given, ∠A:∠D=2:1 and ∠B:∠C=7:5 Let ∠A and ∠B be 2x and X and∠C and ∠D be 7y and 5yFrom the FIGURE,∠A+∠D=180 ∘ (Alternate angles are supplementary)⇒2x+x=180 ∘ ⇒3x=180 ∘ ⇒x= 3180 ∘ =60 ∘ And,∠B+∠C=180 ∘ (Alternate angles are supplementary)⇒7y+5y=180 ∘ ⇒12y=180 ∘ ⇒y= 1218 ∘ =15 ∘ Hence,∠A=2x=2×60 ∘ =120 ∘ ∠D=x=60 ∘ ∠B=7y=7×15 ∘ =105 ∘ and ∠C=5y=5×15 ∘ =75 ∘ |
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