1.

ABCDEF is a regular hexagon. If bar(AB)=bar(a), bar(BC)=bar(b)" then "bar(CE)=

Answer»

`(BAR(B)-2BAR(a))`
`2(bar(a)-bar(b))`
`bar(b)-bar(a)`
`bar(a)-bar(b)`

ANSWER :A


Discussion

No Comment Found