Saved Bookmarks
| 1. |
ABCDEF is a regular hexagon with point O as centre. Find the value vec(AB)+vec(AC)+vec(AD)+vec(AE)=vec(AF). |
|
Answer» SOLUTION :From the diagram `(vecAB)=-(vecDE)(vec BC=-vec EF)` `vec(AB)+vec(AC)+vec(AD)+vec(AE)+(vecAF)` `cancel vec(AB)+(cancel vec(AB)+cancel vec(BC))+vec(AD)+(vec(AD)+cancel vec(DE))+(vec(AD)+cancel vec(DE)+cancel vec(EF))` `=3vec(AD)=3(2vec(AO))=6(vec(AO))` |
|