Abhinesh travels to his friends house in 6 1 upon 2 hours at a speed o

1.	Abhinesh travels to his friends house in 6 1 upon 2 hours at a speed of 50 km per hour but on his return journey he covers the same distance in 5 hours what is the distance what is his speed on the return journey
Answer» ANSWER:- As we KNOW, Average speed = Total distance/Total Time Distance COVERED in 30 min with the speed of 50 km/hr = 50 × 1/2 = 25 km Distance covered in 20 min with the speed of 60 km/hr = 60 × 1/3 = 20 km Average speed = [(25 + 20)/(20 + 30)] × 60 Average speed = 45/50 × 60 Average speed = 54 km/hr Step-by-step explanation: *PLEASE MARK ME AS THE BRAINLIEST*

Abhinesh travels to his friends house in 6 1 upon 2 hours at a speed of 50 km per hour but on his return journey he covers the same distance in 5 hours what is the distance what is his speed on the return journey

Answer»

ANSWER:-

As we KNOW,

Average speed = Total distance/Total Time

Distance COVERED in 30 min with the speed of 50 km/hr = 50 × 1/2 = 25 km

Distance covered in 20 min with the speed of 60 km/hr = 60 × 1/3 = 20 km

Average speed = [(25 + 20)/(20 + 30)] × 60

Average speed = 45/50 × 60

Average speed = 54 km/hr

Step-by-step explanation:

PLEASE MARK ME AS THE BRAINLIEST