1.

AC = CO = D , S_(1) C = S_(2) C = d ltlt D A small transparent slab containing material of mu = 1.5 is placed along AS_(2). What will be the distance from O of the principal maxima

Answer»

`D/4`
`-D/5`
`D/10`
`-D/16`

Solution :Path difference = `2d SIN THETA + (mu -1) l`
`therefore ` For principal maxima
`2d sin theta + 0.5 l = 0`
`sin theta_(0) = (-l)/(4d) = (-1)/(16)(because l = (d)/(4))`
`therefore` OP = D `TAN theta_(0) = -(D)/(16)`


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