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Acceleration due to gravity on moon is `1//6` of the acceleration due to gravity on earth. If the ratio of densities of earth `(rho_(e))` and moon `(rho_(m))` is `((rho_(e))/(rho_(m)))=5/3` then radius of moon `(R_(m))` in terms of `R_(e)` will beA. `5/18 R_(e)`B. `1/6 R_(e)`C. `3/18 R_(e)`D. `1/(2sqrt(3)) R_(e)` |
Answer» Correct Answer - A |
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