Saved Bookmarks
| 1. |
Acceleration of a particle at any time t is veca=(2thatj+3t^(2)hatj)m//s^(2).If initially particle is at rest, find the velocity of the particle at time t=2s. |
|
Answer» Solution :Here ACCELERATION is a FUNCTION of time.i.e, acceleration is not constant.So, we can not APPLY `vecv=vecu+vecat` We will have to go for intergration for dinding velocity at any time t.This `dvecv=dvecadt` or `underset(0)underset(vecv)intdvecv=underset(0)overset(2)intvecadt` (or) `vecv=underset(0)overset(2)int(2thati+3t^(2)hatj)dt=[t^(2)hati+t^(3)hatj]_(0)^(2)=(4hati+8hatj)m//s` Therefore,velocity of particle at time =2s is `(4hati+8hatj)m//s` |
|