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Acceleration of a particle in SHM at displacement `x=10 cm` (from the mean position is `a =-2.5 cm//s^(2)`). Find time period of oscillations. |
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Answer» Correct Answer - A::B::D Time period is given by `T = 2pisqrt(|(x)/(a)|)` Substituting the values we have, `T = 2pisqrt((10)/(2.5)) = (4pi)s` |
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