1.

According to 2nd law of Faraday's electrolysis the correct one is i) (" wt. of "H_2 " liberated")/("wt. of " Cl_2 " librated") = ("eq. wt . of" H_2 )/(" eq. wt . of " Cl_2) ii) (m_(Ag))/(m_(cu)) = (E_(Ag))/(E_(Cn)) iii) (m_(Ag))/(m_(Cu)) = (E_(Cu))/(E_(Ag))iv) (m_(H_2))/(m_(Cu)) = (E_(H_2))/(E_(Cu)) The correct combination is

Answer»

only II, IV
only i
only I, ii, iv
only ii, III


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