1.

According to Arrhenius equation, rate constant k is equal to "A e"^(-E_(a)//"RT"). Which of the following options represents the graph of ln k vs (1)/(T) ?

Answer»




Solution :`K="A e"^(-E_(a)//"RT"):.lnk=lnA-(E_(a))/(RT)`. Hence, graph of LN k vs `(1)/(T)` will be linear with negative slope and INTERCEPT = ln A, i.e., (a).


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