1.

According to Arrhenius equation rate constant k is equal to A e^(-E_(a)//RT).Which of the following options represents the graph of In k va (1)/(T)?

Answer»




Solution :K=`A e^(-E_(a)//RT)`
`therefore` In k=In `(A e^(-E_(a)//RT))`
`therefore` k=In `A-(E_(a))/(RT)`
`therefore`

k=`Ae^(-E_(a)//RT) therefore` In k=In `-(E_(a))/(R )`Here ,graph of In k vs `(1)/(T)` will be linear with negative SLOPE and INTERCEPT =In A,i.e (A)


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