According to Bolir's theory, the energy of an electron in hydrogen atom starts corresponding to n=1,2,3,4 is -13.6 eV, -3.4 eV, - 1.51 eV and -0.85 eV respectively. In order to obtain emission of H_(beta) line of Balmer series, the energy that has to be given to a normal hydrogen atom is

According to Bolir's theory, the energy of an electron in hydrogen ato

1.	According to Bolir's theory, the energy of an electron in hydrogen atom starts corresponding to n=1,2,3,4 is -13.6 eV, -3.4 eV, - 1.51 eV and -0.85 eV respectively. In order to obtain emission of H_(beta) line of Balmer series, the energy that has to be given to a normal hydrogen atom is
Answer» `12.75eV` `14.45eV` `2.55eV` `4.25eV` SOLUTION :The hydrogen atom in the ground state `(-13.6eV)` MUST be excited to the energy LEVEL with n = 4 (i.e., `-0.85eV`) must be excited to the energy level with n = 4 (i.e., `-0.85eV`) so as to have `H_(BETA)` line.

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According to Bolir's theory, the energy of an electron in hydrogen atom starts corresponding to n=1,2,3,4 is -13.6 eV, -3.4 eV, - 1.51 eV and -0.85 eV respectively. In order to obtain emission of H_(beta) line of Balmer series, the energy that has to be given to a normal hydrogen atom is

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