1.

According to Charles' law, at constant pressure 100ml of a given mass of a gas with 10^(@)C rise in temperature will become( ( 1)/( 273) = 0.00366)

Answer»

1.100.0366
2.99.9634
3.103.66
4.100.366

Solution :`V_(t) = V_(0) + V_(0) XX 10 xx 0.0036`
`= 100 + 100 xx 10 xx 0.0036`
`= 103.66`


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